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C#定义多行字符串的方式

在定义的前面加上@符号：

1             string aa = @"asdfsdfsd2                         fsdsfsdfsdfsdfsdfsdfs3                         safasfsadfsdfasfsfsdfsd ";

在C#中拼接字符串有几种方法

1. 利用  JsonConvert.SerializeObject方法 (Nuget获取Newtonsoft.Json Package)

1             string uid = "22"; 2  3             var abcObject = new 4             { 5                 AccessKey = 11, 6                 CustomerNo = uid, 7                 mc = "33", 8                 qd = "44", 9                 mr = "55",10                 insertDate = DateTime.Now11             };12             string serJson = JsonConvert.SerializeObject(abcObject);

2. 利用StringBuilder

1             StringBuilder str = new StringBuilder();2             str.Append("{");3             str.Append("AccessKey:\"" + 11 + "\",");4             str.Append("mc:\"" + 22 + "\",");5             str.Append("qd:\"" + 33 + "\"");6             str.Append("}");7             string serJson = str.ToString();

3. 直接拼接字符串

1         string serJon = "{AccessKey:\"" + 11 + "\",mc:\"" + 22 + "\"}";

4. 利用StringFormat

1             string mc = "22";2             string id = "11";3             string serJson = string.Format("[{
 { AccessKey:\"{0}\",mc:\"{1}\"}},{
 { AccessKey:\"{2}\",mc:\"{3}\"}}]", id, mc, "33", "44");

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